4/5 test cases have passed...1 hidden test case not passed...can someone help me?..what might that case be?..whats wrong here?

Question

Input Format:
A string of random letter characters (no numbers or other buttons were pressed).

Output Format:
A string that says 'Deja Vu' if any letter is repeated in the input string, or a string that says 'Unique' if there are no repeats.

Sample Input:
aaaaaaaghhhhjkll

Sample Output:
Deja Vu

Explanation:
Your program should output 'Deja Vu' because there are many repetitions in 'aaaaaaaghhhhjkll'.

a = input()
b = list(a)
temp = []
con = False
for i in b:
if i in temp :
print('Deja Vu')
con = True
else:
temp.append(i)
if con == False :
print('Unique')
else :
pass

Answer 1

Chinmay Bhalerao This is the correct version of ur code.

a = input()
b = list(a)
temp = []
con = False
for i in b:
if i in temp:
con = True
break
else:
temp.append(i)

if con == False:
print('Unique')
else:
print('Deja Vu')

Answer 2

If repeated, print Deju Vu and exit loop..

Edit:
For aaabc, It printing 2times Deja Vu. Need only one time.

Answer 3

Chinmay Bhalerao
text = input()
if sorted(set(text)) == sorted(text):
print("Unique")
else:
print("Deja Vu")

This is an easy way. What set() does is that it removes any duplicates, so if after removing duplicates and before removing duplicates is the same, print unique, otherwise dejavu.