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What is the equivalent of vector<double> (of C++) in Python ?
Hi everyone! I am trying to re-write the same program that I made in C++ but in Python. In a function I used vector<double> for get its size(), its back() and its end(). And I would like to know what the best function or technique, just the equivalent of those in Python. Thanks to all that would answer me 😊
4 Antworten
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Vector has `size`, `front` and `back` method. But I'm not sure about `end`. Did you mean vector iterator?
I was thinking a Python `list` maybe was what you want. But just for the sake of clarity, I'd prefer to see your C++ code first. So I suggest you to attach the code link in the thread Description 👍
Follow this guide just in case you didn't know how to share links 👇
https://www.sololearn.com/post/75089/?ref=app
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This is my code Ipang
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Siyam
There are some problems with the C++ code. Please fix the problems, currently the code is not running.
Can you elaborate about what the code should do? I have no idea what the code is supposed for. Need more info sspecially about the `calc` method.
I edited your code and added a few comments.
https://code.sololearn.com/cdhT442T41R1/?ref=app
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#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <vector>
#include <iomanip>
using namespace std;
class temperature {
public:
temperature();
~temperature();
void calc(unsigned int);
protected:
private:
vector<double> _queue;
double _g;
int switches;
}
temperature::temperature()
{
this->switches = 0
}
temperature::temperature()
{
}
void calc(unsigned int period) {
if (this->_queue.size() <= period){
return;
}
this->_g = 0;
for (size_t counter = this->_queue.size() - period; counter != this->_queue.size(); counter++) {
double tmp = this->_queue[counter] - this->[counter - 1];
this->_g += (tmp > 0 ? tmp : 0);
}
this-> /= period;
}
int main() {
return 0;
}