not equal to, if(j!=3,4,5)

Question

public class Program
{
public static void main(String[] args) {
double S=0;
double n=4;
double j=1;
do{
if(j!=3,4,5)
S=S+ Math.pow(1/(2*j+3),j/3.0);
j++;
System.out.println("S="+S + "j="+j);
}
while(j<=n+2);

}
}

Answer 1

Angel Halili
public class Program
{
public static void main(String[] args) {
double S=0, j=1;
int n=4;
do{
if(j==1 || j==2)
S=S+ Math.pow(1/(2*j+3),j/3.0);
j++;
System.out.println("S="+S + "j="+j);
} while(j<=n+2);
}
}

Answer 2

It doesnt output anything ...

Answer 3

(j! =3,4,5) here it is equal to j!=3 only.. And false (since j=1)

while(j<=n+2); (1<=4) always true because j value not changing so Infinite loop.. Terminates after timeout..
Edit:
Again give some description.

Answer 4

While calculating the sum , (j) shouldnt be equal to 3 4 5

Answer 5

So when j=1 it goes (1/2+3)^(1/3.0), when it comes to j= 3 , 4 , 5 it shouldnt calculate

Answer 6

Angel Halili

public class Program
{
public static void main(String[] args) {
double S=0;
//double n=4;
double j=1;
int n=4;
do{
if(j!=3 && j!=4 && j!=5) //Edit use && instead of ||
S=S+ Math.pow(1/(2*j+3),j/3.0);
j++;
System.out.println("S="+S + "j="+j);
} while(j<=n+2);
}
}

Edit:
If there is no difference in taking int type values in place of double type values, use Integer type only.....
Above for n and j, int n,j; is better than double j, n;

Answer 7

It still calculates 3 4 and 5

Answer 8

Changing at int it effects the sum

Answer 9

Oh. You want when j equal to 1 or 2, s should be calculated else not...?
I edit it...
Edit:
Angel Halili
use && in place of ||
I edit the code above also.. Check again..

Answer 10

Thank you for your time