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Please explain this code in simpler terms for me.
int [ ] myArr = {6, 42, 3, 7}; int sum=0; for(int x=0; x<myArr.length; x++) { sum += myArr[x]; } System.out.println(sum); // 58
1 Antwort
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This program first initialzes an array whose name is `myArr`.
Then initializes `sum` variable to 0.
In for loop during each iteration value of `x` is incremented by 1. From 0 to 4.
. Because of condition `x<myArr.length` when x becomes 4 loop brakes and control is transferred to statement immediately after loop.
Inside loop `x` is used as index to access each element of array `myArr` one by one.
`sum+= myArr[x];` is same as
`sum= sum + myArr[x];`
This loops adds all the elements to variable `sum`.
So finally value of variable `sum` is equal to sum of all elements in array. (6+42+3+7 = 58)
If you still don't understand it I'll suggest you to start course from very beginning also check tutorial on official website (https://docs.oracle.com/javase/tutorial/). Don't ignore any concept , try to write code. Just reading is not enough.