How can we calculate square root without using any built-in function in python?

Question

There is already a function in module "math" of python called "sqrt()". But if I want to calculate the square of a number without using the "sqrt()", how can I do that? Is there any formula or any method for it?

Answer 1

there are two more ways currently I can refer(without using sqrt())

x = int(input())

import math
print(pow(x, 0.5))

or,

print(x**0.5)

Answer 2

A very god question tho

Answer 3

You can for instance say; root = Number**2.
but why don't you want to use math.sqrt or one-half power? I see two main reasons to avoid that: when you need more precision than the rest significant digits that math.sqrt and one-half power provide, or you are working with large integers and you want an exact answer for the integer part of the square root.

Answer 4

Try this new method without using sqrt() and pow()

num = float(input("Enter num: "))
a = 1.0

while(1):
b = a*a
if num-0.1 < b < num+0.1 :
break
else:
pass
a = a + 0.01

print("\n Square root value is: ",round(a,2))

Hope its helpful

Answer 5

No, it isn't a homework question, a thought just passed through my mind and I couldn't find the anwer to it myself, even though it was easy😅

Answer 6

# square root
a=int(input("enter no."))
b=a**0.5
print(b)

Answer 7

https://code.sololearn.com/c4DRJH1LnRHO/?ref=app

Answer 8

https://www.geeksforgeeks.org/square-root-of-an-integer/

Check that out.

Answer 9

x**0.5