I fail to pass sololearn tests

Question

My regards to everyone.
I am trying to solve every riddle in sololearn environment but I got stuck with the one called "convert date from US to EU'", particularly with passing sololearn tests. When I test it by myself in full python environment, every input gives me a desired outcome, however the code fails to pass some sololearn tests. Can you please give me a hint where to look at.
Here is my code, I hope I did the right way reffing to it

https://code.sololearn.com/c9UWg5Yebd2u/?ref=app

Answer 1

You can also try this approach!!!!

import re

months = ["January", "Febuary", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

s= input()

if bool(re.search('[a-zA-Z]', s)):
n=months.index(re.findall('[a-zA-Z]+', s)[0])+1
date=s.split(',')
print(re.findall('[\d]+',date[0])[0]+'/'+str(n)+'/'+date[1].strip())
else:
n=s.split('/')
print(n[1]+'/'+str(n[0])+'/'+n[2])

Answer 2

you should put a space after the comma, the input must fit the codecoach instructions
'November 01, 2010'

Answer 3

Rik Wittkopp string isn't a keyword ;)

The rest I fully agree with.

Answer 4

Wow, thank you very much guys for brain storming ♥️ this feeling when strangers help you to solve a problem is just amazing, if only in every domain of life it's implied

Answer 5

I think that with every test just another skill of coding that we got is tested. For example, for this task they want to test us how to create a function🙆

Answer 6

I think that in output2 you should print splt_string[2] instead of date[1]

output2 = '{}/{}/{}'.format(int(date[0]), month_dict[month], splt_string [2])

Answer 7

Russ Thanks for the correction.
I will review........again 😁

Answer 8

Not a keyword, ok 😅

Answer 9

Code Crasher I thought that might be the case too🤔

Answer 10

Oh, I got it, I thought there is no space in 19,2019

Answer 11

Code Crasher my code is just for the challenge so I don't validate the input, but you are right in your point.

Answer 12

Rik Wittkopp I converted it into a int() in case if input is '01/01/2010' and output must be '1/1/2010'. I didn't know about 'string' being a keyword, thank you for your answer

Answer 13

Just go back and read the chapter again is the good idea

Answer 14

no, splt_string contains ['month_name', 'date_no,', 'year'] as Russ said it.

Answer 15

us=input()
def temp(month):
month=month.lower()
d={"january":1,'february':2,'march': 3,'april':4,'may':5,'june':6,'july':7,'august':8,'september':9,'october':10,'november':11,'december':12}
m=str(d[month])
return m

if "/" in us:
us=us.split('/')
eu=[]
eu.append(us[1])
eu.append (us[0])
eu.append(us[2])
eu="/".join(eu)
else:
us=us.split (' ')
eu=[]
euu=us[1].split (',')
eu.append(euu[0])
eu.append (temp(us[0]))
euuu=euu[1]
eu.append(us[2])
eu='/'.join(eu)

print(eu)

Answer 16

Looking at it now

Answer 17

Your code doesn't pass the second test and I think won't pass any test in that format.

In your second section, string.split() will give you

['month_name', 'day_no,', 'year']

but you seem to treat it like the day and the year will appear in the same element as each other.

Answer 18

Shamil Erkenov
Ok buddy.
The main problem seems to be that when an input is something like November 17, 2009 your output does not generate the year.

Might I also suggest that you replace the word string with date.
string is a python keyword which may cause confusion with the program.
Also, I don't think you need to convert aspects of your string into integers as you are not doing any math.
See how you go.
Please excuse me for not providing a direct answer, but code coach is all about being able to resolve the problem yourself.

Answer 19

Shamil Erkenov did you try what I suggested? replace date[1] with splt_string[2] in output2

output2 = '{}/{}/{}'.format(int(date[0]), month_dict[month], splt_string [2])

I don't think it's a date validation problem.

Answer 20

I just tested it, SIGH!
I thought it operated like int or float, but now I know better.
Thanks guys. 😁👍