python(tuple)

Question

def fibo (n):
a ,b = 0,1
for i in range(n):
print(a)
a,b = (b , a+b)
we say tuples are immutable and we cant change the vale of tuples but in this function which follows the Fibonacci sequence the value of a & b are changing each time the for loop runs
how it can be?
the a & b are not tuple or what?

Answer 1

a,b are integers not tuple!

Answer 2

In the line a,b = (b, a+b), the tuple is being "unpacked". a is taking on the value of b, b is taking on the value of a+b. The tuple then ceases to exist.
In fact, the line will work the same without parentheses - a,b = b, a+b

Answer 3

If you write a=0,1 or b=0,1 it this case these variables recognized as tuples, but a,b=0,1 is multiple definition with assign.
so this entry the same as
a=0
b=1
but in python code manner

Answer 4

)))) you have inccorect code. There are not fibonachi numbers))))

So loook 0,1

1,1+1
2,2+2

Answer 5

)))) oooooo loooook you really forgot that operator = is from right to left.
In your first code everything was ok. So your code was in python manner.

Thrn you change code on c++ code manner but forgot than you need
But in this case a eq b and b = a+b not the same as python a,b= b,a+b)))

Answer 6

So 1 code ok. But there are not tuple they are integers.
A,b=b,a is the python swapping code.
So a,b=0,1is a0 b1

But a,b=b,a is the same as

c=a
a=b
b=c

And this procedure do in python interpeter.

Answer 7

Thanks russ and george

Answer 8

def fibbi(n):
a = 0
b = 1

for i in range(n):
print(a)
a = b
b = a + b

ok i change the method because you say a and b are int but the output answers are not true

Answer 9

Sorry could youplease add full code. I could not understand what you mean about output answers are not true

Answer 10

n in both is 5

def fibbi(n):
a = 0
b = 1
for i in range(n):
print(a)
a,b = b,a+b
n = int(input())
fibbi(n)

anwsers : 0 1 1 2 3

********************

def fibbi(n):
a = 0
b = 1
for i in range(n):
print(a)
a = b
b = a+b
n = int(input())
fibbi(n)

anwsers : 0 1 2 4 8