I made a generator to make a group from a pool of players but I can only make 1 group ,

Question

https://code.sololearn.com/cyC0xHINuJMh/?ref=app

How do I make a second and third group without including any of the people from the first group

Answer 1

a = "".join([random.choice(str1)for x in range(1) ]) # why are you doing it this way?
Although it will work......, here's how I would do it..
(but you must change your tuples to lists for this to work.)
a = random.choice(str1)....then...
str1.remove(a)
Now the element chosen by the random.choice has been removed from the str1 ready to start your group2 selections.

Answer 2

Thank you for writing the code , I will try to understand it and learn from it

Answer 3

rodwynnejones I searched it on internet ad I've only done a small part of the python course ,so where exactly would I put the str1.remove(a) , after the variable a or at the end after print and thanks for assisting me

Answer 4

a = random.choice(str1)
b = random.choice(str2)
c = random.choice(str3)
d = random.choice(str4)
str1.remove(a)
str2.remove(b)
str3.remove(c)
str4.remove(d)
group1 = a + b + c + d
print(group1)
# Now start the code for group 2.
# Although you can put this code in to a "for loop"
# and append to a pre-declared list eg "groups" then
# unpack into "group1", "group2", "group3" etc...
# just to add...are you sure you need str4, as the same name
# can be picked twice as str4 is str1 + str2 + str3?
# but that's up to you.

Answer 5

Thank you, I'm using str 4 so it cam be a group of 4 , if it produces the same name twice I just re run it

Answer 6

And the for loop is abit complicated for me as I'm still new and trying out stuff with what the basics i know

Answer 7

rodwynnejones I see the method with remove works but is very long , I will try to look into and understand the for method

Answer 8

Once you put it into a loop it's not that long:-
https://code.sololearn.com/cle445E1HhTn/#py