+ 2

Please tell why this isn't working

var value = "1 (555) 555 5555"; // checks if value contains any brackets. Returns true if not console.log(/[^()]/.test(value)) Why doesn't it return false? It returns true. Please check

23rd Apr 2020, 7:36 PM
Sajid
Sajid - avatar
14 Antworten
+ 4
sajid chowdhury Ah... I see the issue. Even though parentheses exist in "1 (555) 555 6555", the pattern /[^()]/ matches as true because it's actually checking that there is at least one character that isn't a parenthesis. Therefore, to check that none of the characters are parentheses, the pattern would need to check every character from start to finish as seen in this pattern: /^[^()]+$/ I've updated the code to include this line to show this in action. -------- test("Test for NO parentheses:", /^[^()]+$/, values) ---- Or you can test this with your version of the code: -------- var nums= "1 (555) 555 6555"; console.log(/^[^()]+$/.test(nums)) ----
24th Apr 2020, 2:17 AM
David Carroll
David Carroll - avatar
+ 6
sajid chowdhury Your updated code should work. You don't need to escape the parentheses when contained within the brackets. The original regex was missing the character class brackets []. That said, I put together some additional variations for you to review. Hopefully, these will be helpful. https://code.sololearn.com/WyTMcT7M6XFg/
23rd Apr 2020, 10:35 PM
David Carroll
David Carroll - avatar
+ 5
It looks like David has taking under his wing, you should be squared away now. I still suggest you check out regexr.com it will help you grain better understanding of regexp.
23rd Apr 2020, 10:52 PM
ODLNT
ODLNT - avatar
+ 3
This (/^()/) is not checking if value contains parens. As is you are checking for any of the patterns specified within the parens (), which is nothing. You are testing for nothing at the beginning of string value. Hence the reason the return is true because nothing is at the beginning of string value. With snippet as-is, you need to escape the parens (/^\(\)/). But this just tests if the string starts with empty parentheses. https://www.w3schools.com/jsref/jsref_obj_regexp.asp https://code.sololearn.com/WUxFIpDnZf8O/#js
23rd Apr 2020, 9:54 PM
ODLNT
ODLNT - avatar
+ 2
sajid chowdhury The latest change /[^\(\)]/ it appears that it will work, Testing to match every character that is not an opening or closing paren. Is that what you want? You should check out this site to help regexr.com/536ls
23rd Apr 2020, 10:43 PM
ODLNT
ODLNT - avatar
+ 2
sajid chowdhury I'm glad that code was helpful. I've cleaned it up a bit if you want to review it again.
23rd Apr 2020, 11:00 PM
David Carroll
David Carroll - avatar
+ 1
🔫 Rick Grimes why can't I use a shorter code? Like the one above?
23rd Apr 2020, 9:37 PM
Sajid
Sajid - avatar
+ 1
David Carroll thanks a lot Sir, for replying
23rd Apr 2020, 10:43 PM
Sajid
Sajid - avatar
+ 1
David Carroll shouldn't the test return false if there are any brackets? But it isnt doing that for me. var nums= "1 (555) 555 6555"; console.log(/[^()]/.test(nums)) this returns true which it shouldn't. pls check a bit. I'm also going to update code above
23rd Apr 2020, 11:02 PM
Sajid
Sajid - avatar
+ 1
David Carroll works perfectly. Thanks a lot.
24th Apr 2020, 9:18 AM
Sajid
Sajid - avatar
0
If you want to check for any type of bracket, you need to check for all of it. I don't know if this is best way to do it but this will do your job. console.log(!/[(,),{,},<,>,\[,\]]/.test(value))
23rd Apr 2020, 8:35 PM
Raj Chhatrala
Raj Chhatrala - avatar
0
ODLNT I've changed my code. Please check now
23rd Apr 2020, 10:11 PM
Sajid
Sajid - avatar
0
ODLNT I basically want to check if there aren't any parentheses. If there are ,3 digits should be between them. Having a hard time,just to solve this little problem. Now hopefully mr mods answer would be correct
23rd Apr 2020, 10:46 PM
Sajid
Sajid - avatar
0
Your regex find the pattern that initiate with a parentheses ( and the next character is the other parentheses ). Your regex might be /[^(.)]/
24th Apr 2020, 8:20 AM
Jonathan Alvarado
Jonathan Alvarado - avatar