[SOLVED] When I loop an Array, and I want to make an if else statement with the array.next() block. What can I do?

Question

It doesn't work because it's not a string and tbe if else statement says 'false', how can I fix it?
https://code.sololearn.com/c9UOuV3KiZjJ/?ref=app
Thanks

Answer 1

ArrayList corr = new ArrayList();

When you create an ArrayList like this, then all values will be from type Object.

Array<Character> or ArrayList<String> list = new ArrayList<>()

Now the list knows the type.

== works only for primive data types (int, char, double...)

But String is an object. If you compare objects you have to use equals.

if(myString.equals(anotherString)){

And why are you using try / catch?

Answer 2

No. I am not sure what.you want to do:

a) convert int to string
b) try a hashmap
c) use two arrays

Answer 3

I'm using try catch because if the index is bigger than the length of the list, it throws an error. Anyway thanks for the information

Answer 4

Orango Mango

I understand it. ;)

But instead of catching such exceptions you should avoid them.

You know the length and you know that the index starts at 0.

Instead of an iterator you can use a normal loop:

for(int i = 0; i < current.length - 2; i++){

i cannot be larger than current.length - 2 so you will not get a problem if you search for an index i + 2

Answer 5

No. This won't work.

Answer 6

Thanks, but can I make an Array with more Objects type like <String><Int> ?

Answer 7

So I can't make an Array containing Ints and Strings?