Why output is 12?

Question

#include<stdio.h>
int main()
{
int a,b=5;
a=++b;
printf("%d",a+b);
return 0;
}

Answer 1

Well b=5. Alright then a=++b. This will first increment b (b=b+1) which will make it equal to 6, then it will assign its value to a (so a=b=6).
Therefore, a+b=6+6=12
I hope it's clear...

Answer 2

You're welcome Kawser I'm glad I could help 👍👍

Answer 3

a = 0, b = 5
a = 6 (since a = ++b) now b = 6 (since ++b)

a+b = 6 + 6 = 12
printing we have 12

++b increment the value of b first before used.
a = ++b in this case the increment value would be assigned to a.

b++ first used then the value is incremented.
a = b++ in this case the value of b is assigned to a without incrementing and then b is incremented.

Answer 4

thanks to all.its clear now