Why isn't the for loop being executed even once in this code? Even when k=0

Question

What does the goto statement really do here?
#include <stdio.h>

int main() {
int i = 0,k;
if(i==0)
goto label;
for(k=0;k<3;k++)
{
printf("hi\n");
label: k=printf("%03d",i);
}

return 0;
}

Answer 1

When label executes k=000 so Loop becomes false and doesn't runs but 000 will be printed as it should
Try changing %03d to %d and it will run the loop infinitely as 0hi ,0hi ..

Answer 2

Yup looks like I don't know c so I can't tell how goto works but seems like label is also executed in for loop everytime , otherwise it would have just print for %d
0hi
hi
hi
hi
0hi
hi
hi
hi
But that's not happening

Answer 3

Int i= 0 that was the initialized value.
Check for the condition
If(i==0)
Goto label;
That's why it's not entering the loop. Try changing this value. Int i= something else...not zero.,k;

Answer 4

Vishal Srivastava got that but after the label is executed i. e. after k is printed shouldn't it check if k<3 or not and print "hi"

Answer 5

Because k=0 everytime label runs for %d

Answer 6

Abhay and again why does it run infinitely. Why not till k <3?

Answer 7

Abhay so the label statement gets executed even when there's no goto statement inside the loop?