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Does anyone know how to write a code which comes out like a list in C++
A code which brings an output like this Line. Asterisk 1. * 2. ** 3. *** 4. **** 5. ***** 6. ****** 7. ***** 8. **** 9. *** 10. ** 11. *
18 Antworten
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Please help put
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Have you tried to solve the task? Can you show us that attempt?
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Okay sure
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#include <iostream>
Using namespace std;
int main()
{
cout<<"Line"<<endl;
for(int x=1;x<=19;x++){
cout<< x <<endl;
}
int row=0;
int nasterisk;
for(row=1;row<=10;row++){
nasterisk;
cout<<"\t\t";
for(nasterisk=1;nasterisk<=row;nasterisk++){
cout<<"*";
cout<<endl;
}
for(row=9; row>=0;row--){
cout<<"t\t\";
for(nasterisk=1;nasterisk<=row;nasterisk++)
cout<<"*";
cout<<endl;
}
}
system("pause");
return 0;
}
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This is the code
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There is some bugs and the code is too long
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Some bugs like?
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Try to put in the code
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How? I don't understand
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#include <iostream>
#include<iomanip>
using namespace std;
int main() {
int line;
cin>>line;
for(int i=0;i<line;i++){
cout<<left<<setw(4)<<i+1;
for(int j=0;j<=(i<=line/2? i:line-i-1);j++){
cout<<"*";
}
cout<<endl;
}
return 0;
}
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That's would work
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Because you cout line before asterisk not with it
That's first
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Mohamed ELomari did you see line number 11 and 12 in output of your code?
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No
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Thanks it worked out
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#include <iostream>
using namespace std;
int d;
int main() {
for(int i=-4;i<=4;i++){ d=5-abs(i);
for(int j=0;j<d;j++)
cout<<"*"; //use printf("*");
cout<<endl;}//use printf("/n");
return 0;
}// abs function is return positive value