How to remove alphabets characters from the input String?

Question

Input : @1456hello13#%+?!/:'*"

Output : @145613#%+?!/:'*"

Answer 1

result = "".join(list(filter(lambda x: not x.isalpha(), input())))
print(result)

Answer 2

Javascript code is wrong

Answer 3

A bit late, but anyway my try with a pure list comprehension:

inp = "@1456hello13#%+?!/:'*"
#Output : @145613#%+?!/:'*"

# if you need to get the result as data
res = ''.join([i for i in inp if not i.isalpha()])
print(res)

# if you only need to print result
print(''.join([i for i in inp if not i.isalpha()]))

Answer 4

In javascript :

const string = "@1456hello13#%+?!:'*";
const withoutChar = string.replace(/[a-zA-Z]/g, '');

console.log(withoutChar);

In python is almost same :

import re
re.sub('[a-zA-Z]', '', string);
print(string);

Answer 5

Black Cap🇮🇳 Hey, lol. I forgot to include that tiny 'g' after /[a-zA-Z]/. Please test it again :))