how does this code works ?

Question

I got this code:

#include <iostream>
using namespace std;

int main() {

int x,y=7;
x=y=8;
y=--x%y;
cout<<y;
return 8;

}
so in the third command first it decreases x so x now is 7 then assigns it to y so y is 7 then what next ?

Answer 1

--x%y will first decrease the value of x from 8 to 7 then get the % modulus (remainder) of x/y. 8 goes into 7, 0 times leaving a remainder of 7. So 7 is returned and y = 7.

Answer 2

x and y both are equals value 8
the x is then decrease when
--x%y so the value of x is 7
7%8 gives the remainer of 7.

Answer 3

you've re-assigned x and y to the value 8...
the x is then pre-decremented so it's now 7.....so..
7%8 gives the remainer of 7.

Answer 4

thanks guys....my biggest Problem was if after the increment it assigns or does the remainder..now clear

Answer 5

thanks guys....my biggest Problem was if after the increment it assigns or does the remainder..now clear