System.exit( )

Question

what is System.exit( ) method?
I seen example code:
class program{
public static void main(String[ ] args){
int x=0;
System.exit();
System.out.println(“1”);
}}
Here output is : error
How does it work....

Answer 1

Indian

Yes. If a method expects arguments than you have to use them when calling this method.

Answer 2

Hello Indian

int x = 0;
int not Int

System.exit() expects an integer as argument.
Normal exit: System.exit(0);
About this method: https://www.baeldung.com/java-system-exit

System.out.println("1") vs. System.out.println(“1”);
It is hard to see but in your code you are not using the normal "".
Your code uses this characters: \u201c and \u201d so you get an illegal character error.

Btw: Because of the exit your last print statement is dead code.

Answer 3

thank you😊 Denise Roßberg
and it is compulsary to pass integer argument in System.exit( ) ?
without we get error ryt...

Answer 4

tq Mirielle