Please Explain why a is not equal to b

Question

https://code.sololearn.com/ca1KKjavIhz2/?ref=app

Answer 1

Because l.sort() function does not return any value, instead it just sort the list "l" . And comparing "none" with a sorted list "b" will return false.

Here👇 see this code for better understanding

https://code.sololearn.com/cbaHIljTN34K/?ref=app

Answer 2

Because as Arsenic said, .sort() does not return any value. It just sorts the list. sorted on the other hand, returns a new list

Answer 3

sorted returns a new list
sort modifies the list you are sorting

Throw some print statements in there and you'll see they are not equal

Answer 4

This is because l.sort() did not return any value thus, "a" is uninitialised.

Answer 5

Run this:

l= [ 1,9,65,88,40 ]

a = l.sort ()
b= sorted (l)

print('a =',a)
print('b =',b)

if a==b:
print (1+1)
else:
print (0)

Answer 6

Arsenic
My internet is a bit slow, like me.
By the time I posted, you gurus had already supplied the perfect answers

Answer 7

Rik Wittkopp this is what my code is doing.

Answer 8

Why it is showing NONE for print(a)