How is byte b accepting +256 when range of byte is -128 to +128.

Question

class ByteShift {
public static void main(String args[])
{
byte a = 64, b;
int i;
i = a << 2;
b = (byte) (a << 2);
System.out.println("Original value of a: " + a);
System.out.println("i and b: " + i + " " + b);
}
}

Answer 1

Specialty of Java type cast - Java allows to store any 256 values as byte if you force it to. And you do by casting int 256 to byte.

Answer 2

No. 257 will overflow and output 1.

Answer 3

The range of a byte has 256 possibilities. The range is -128 to 127. That's 128 negative numbers + 127 positive numbers + the number 0 = 256 possibilities.

Answer 4

So , can't b store 257 ?