Which datatype is to be used for handling values in range 10^18 in c++?

Question

I have tried using
Long long int, unsigned long long int
But it fails for digits greater than 9

Answer 1

You can use boost library. It can handel values beyond 2^64. For more details please check the link below.

www.geeksforgeeks.org/advanced-c-boost-library/amp/

There is a rule by which you can calculate how many digit a data type can store and the logic is 2^10 = 10^3 (nearly)

i.e as long long int is an 64 bit integer, it can support 18 digit number because 2^64 = 10^18(nearly) by the above rule. If you want to handle more digits, you can go for boost library.

Answer 2

~ swim ~ 👏

Answer 3

But I think int will work just fine....

Answer 4

Thank you

Answer 5

~ swim ~ what is c++11 wht 11 denoting .

Answer 6

No, int cant handle such large values