What is the output of this code? And explain how?

Question

my_list=[([]), [()]]
for i in my_list:
print(bool(i), end=" ")

Answer 1

First some basics.

Round braces on its own, ie. empty round braces, creates a tuple.

Round braces around something groups it together and indicates precedence, It says, first evaluate this, then the braces dissapear.
(3+2)*2
5*2
10

Side note:
Round braces with a seperating comma also creates a tuple, as in ([ ] ,) we don't have this in your example

The bool of an empty list is False
The bool of a list containing anything is True.

my_list=[([]), [()]]
for i in my_list:
print(i, type(i), bool(i)) #I changed it a bit

output:
[ ] list False <- Empty list
[( )] list True <- list containing a tuple