C - Why k doesn't change?

Question

#include <stdio.h>

void func(int* x){
x-=5;
}
int main() {
int k = 7;
func(&k);
printf("%d",k);
return 0;
}

Answer 1

You forgot to dereference the pointer ( *x ) in the function.
Now you're just decrementing the pointer itself.

There are no calls by reference (&) in C, FradeAlencar. :)

Answer 2

Ohhh, I read wrong, kkk I thought it was c ++, kkk sorry