I'm Getting a "Too many arguments" error in a shell script. Can anyone explain me the cause of the error? Thank You.

Question

Here is the code:
#!/bin//bash -x

read -p "Enter a year: " year
if [ $(( $year % 4 )) -eq 0 -a $(( $year % 100 )) -ne 0 ] -o [ $(( $year % 400 )) -eq 0 ]
then
echo "The year is a leap year"
else
echo "The year is not a leap year"
fi

Answer 1

Anurag Mondal I guess it happens because the string is split to multiple arguments. Using " we can hold it together.

Answer 2

Try wrapping variable output in double quotes

Answer 3

Yes I finally figured it out. Can you explain why I need to do it? Lijo M Loyid

Answer 4

Oh okay..thanks...but in the above case the input is of integer type...why is it still throwing me an error? Lijo M Loyid