Program of strings is compiling error,would you help me?

Question

#include<stdio.h>
int main()
{
    int str[]={'g','l','o','b','y'};
    printf("A%c ",str);
    printf("A%s ",str);
    printf("A%c ",str[0]);
    return 0;
}

Answer 1

Yaa ok

Answer 2

It's a great deal to get compile, but it is solved in recent code exams I have done

Answer 3

But without any changes in the program,the answer is mentioned , as A character A Ag i guess not sure

Answer 4

The question is the same I have mentioned , and based exam I have attended to the correct answer is something like A character A ag, but when I am running it I am not getting the program compiled.

Answer 5

Ok

Answer 6

I guess, it is may be
printf("%Ac", *str) ;
%s not works on integer array.. So it may be charecter array...

Answer 7

%s is address of the int/string storing name

Answer 8

As far i know, %s returns charecter array or string in c.
Do you want to know the program by removing errors? It need atleast 2 changes to work without any warning.. Otherwise it prints A Ag Ag with warnings...
(If *str, then it returns g)

Edit :
Here this, With good examples:
https://aticleworld.com/format-specifiers-in-c/