Why the following code is not satisfying all test cases of no numerals problem

Question

s=input("")
x=""
if "10" in s:
x=s.replace("10","ten")
print(x)
else:
for char in s:
x=s.replace("0","zero").replace ("1","one").replace("2","two").replace("3","three").replace("4","four").replace("5","five").replace("6","six").replace("7","seven").replace("8","eight").replace("9","nine")
print(x)

Answer 1

Have you tried your code with a few test inputs?

What result did you get?

Answer 2

venkatesh sontyana , in my opinion you shouldn't print the text after replacing 10 in the if clause, because text can contain many numbers and you'll get wrong output. You need just one result => one print statement after you done all.

Answer 3

venkatesh sontyana , no start replacing with the case for 10 and then all other.

Answer 4

venkatesh sontyana , that's not the purpose. If you want to learn something you need to put a lot of effort to get some knowledge.

Answer 5

Input contains 0 to10. (randoms)
venkatesh sontyana Your program either if part executed or else part get executed. But think again, it needs both to execute and print result last..
Edit:
Since you using s.replace instead of char.replace,then no need for loop

Answer 6

Ine test case is failed. Remaining 5 are satisfied

Answer 7

I tried all single digit numerals i got correct output

Answer 8

No no,still i am getting single output

Answer 9

Will u please try it for me

Answer 10

I am trying hard but, i am not getting whats wrong in it

Answer 11

I too got the same idea just now. I am trying in that direction.
Thank you

Answer 12

Additionally to all those mentioned problems, there is no need to execute a replace within a loop over all characters. replace replaces all occurrences within a string.