whay does this warningsay?

Question

https://code.sololearn.com/cUS4P16ZhQGC/#c

#include <stdio.h>
int sort(int arr[], int b);

int main() {
int m, n;
scanf("%d%d", &m, &n);
int arr[20][20];
for(int i=0; i<m; i++) for(int j=0; j<n; j++) scanf("%d", &arr[i][j]);

for(int i=0; i<m; i++){
sort(arr+i, n);
}

for(int i=0; i<m; i++){
for(int j=0; j<n; j++){
printf("%d ", arr[i][j]);
}
printf("\n");
}
return 0;
}

int sort(int arr[], int n){
int temp= 0;
for(int i=0; i<n-1; i++){
for(int j=0; j<n-1-i; j++){
if(arr[j]> arr[j+1]){
temp= arr[j];
arr[j]= arr[j+1];
arr[j+1]= temp;
}
}
}
return 0;
}

/*Following is the warning that occured but the output is correct for all inputs. what is this...
./Playground/file0.c: In function 'main':
./Playground/file0.c:11:17: warning: passing argument 1 of 'sort' from incompatible pointer type [-Wincompatible-pointer-types]
11 | sort(arr+i, n);
| ~~~^~
| |
| int (*)[20]
./Playground/file0.c:2:14: note: expected 'int *' but argument is of type 'int (*)[20]'
2 | int sort(int arr[], int b);
| ~~~~^~~~~
*/

Answer 1

Yeah But Problem is Solve.
Thank you for Sharing you Programm Bug.

Answer 2

Use pointer While calling sort
sort(*(arr+i), n) ;

Answer 3

Problem solve
#include <stdio.h>
int sort(int arr[], int b);

int main() {
int m, n;
scanf("%d%d", &m, &n);
int arr[20][20];
for(int i=0; i<m; i++) for(int j=0; j<n; j++) scanf("%d", &arr[i][j]);

for(int i=0; i<m; i++){
sort(arr[i], n);
}

for(int i=0; i<m; i++){
for(int j=0; j<n; j++){
printf("%d ", arr[i][j]);
}
printf("\n");
}
return 0;
}

int sort(int arr[], int n){
int temp= 0;
for(int i=0; i<n-1; i++){
for(int j=0; j<n-1-i; j++){
if(arr[j]> arr[j+1]){
temp= arr[j];
arr[j]= arr[j+1];
arr[j+1]= temp;
}
}
}
return 0;
}

//you define
sort(arr + i, n ) --> wrong you not add array with number you need pass number in array
like below

sort(arr[i] , n)
Problem solve you declare above sort function like i defined.

Answer 4

Mohammed Qadir khan thanks
Has the error occured because arr+i is a pointer and arr[i] is an array..?
Sort() expects an array but a pointer is passed is that right?

Answer 5

Thanks

Answer 6

My Pleasure.