How to link html pages according to user URL input in Django?

Question

A link for example: 127.0.0.1:8000/wiki/html
I want to link to that HTML page where the user types a link, after ...wiki/name_of_page. The stored html pages are in "encyclopedia/name_of_page.html"

So if I enter now: 127.0.0.1:8000/wiki/css it must load the "encyclopedia/css.html" page.

I don't want to hardcode the url in the views.py in search function. So what is the way to link to the page according to user search.

urls.py code is:
from django.urls import path
from . import views

urlpatterns = [
path("", views.index, name="index"),
path("wiki/<str:search>", views.search, name="search")
]

view.py code is:
from django.shortcuts import render
from . import util

def index(request):
return render(request, "encyclopedia/index.html", {
"entries": util.list_entries()
})

def search(request, search):
return render(request, "encyclopedia/name_of_page.html", { # make the url changeable as per the need
"search": search
})

Answer 1

re_path(r'^wiki/(?P<page>\d+)/#x27;, views.getpage, name='page')

#in views.py,
def getpage(request, page):
return render(request, 'encyclopedia/name_of_page.html', {'search' : page})

You can put the imports yourself...
Hope that helps...

Answer 2

from what i seen here https://docs.djangoproject.com/en/3.1/topics/http/urls/

you can directly use search as if its from the url. so try using it.

maybe like
f"encyclopedia/{search}.html"

also, make sure the file exist and the default page if the file doesnt exist

Answer 3

Adarsh Mamgain , instead of making separate pages.. You could make a model and render it in a template.. Also, search for get_object_or_404.