What is the code to round up something

Question

Hello. I'm wondering how do I round up something?

My code
a = int(input())
c = 40
p = 5
x = ((a * p + c)/10 + (a * p + c))
print(x)

Answer 1

Another solution besides the math lib could look like this:

a = int(input())
c = 40
p = 5
x =((a*p+c)/10+(a*p+c))

y = x - int(x) #y now contains everything after the floating point

if y > 0:
x -= y

print(x) #with float point

print(int(x)) #without float point

Answer 2

# use the math library, it makes it easy
import math
a = int(input())
c = 40
p = 5
x = ((a * p + c)/10 + (a * p + c))
print(math.ceil(x))

'''
https://realpython.com/JUMP_LINK__&&__python__&&__JUMP_LINK-rounding/
'''

Answer 3

Codex you should try using Google or any search engine of your choice maybe!

Answer 4

Christian Hauck Thanks man, but that doesn't seem to work I'm not quite sure why. I needed the code for the paint cost challenge and I tested yours and it can't pass the test.

Answer 5

Codex huh odd, i tried it once more and everything seems to be working as expected.

https://code.sololearn.com/cLZo2T1UkbXc/?ref=app

Answer 6

Oooh i found my problem >~<
Was roundig down and not up.

Gotta add +1 to x after the if...

Answer 7

Oh yeah its working fine now thanks!

Answer 8

Thank you so much! your a life saver I've been stuck with this problem for hours