Fill in the blanks to declare a function that returns the square of its argument, call it with the value 42 using a function poi

Question

int sqr(int n) {

return

n * n;
}
int (

*

fp)(int) = sqr;
int x = fp(

42

);

Answer 1

Here blank not showing i fixed your program see this

#include <iostream>
using namespace std;
int sqr(int n) {

return
n * n;
}
int main() {

int (
*
fp)(int) = sqr;
cout<<fp(
42
);

}

Answer 2

Fill in the blanks to declare a function that returns the square of its argument, call it with the value 42 using a function pointer.

int sqr(int n) {

return
n * n;

}

int (
*
fp)(int) = sqr;

int x = fp(
42
);

Answer 3

Where is blanks..? What is your question actually?

Answer 4

1.) return
2.)*
3.)42