What does it mean and how?

Question

int main(){
int a=6;
char c= 5;
printf("%d",!(a==c));

and output: 1

I am confused 🤯

Answer 1

Kritima Tharu Simple,see here a=6,c=5,and when u compare (a==c),it's false and !(a==c) is true, which is why it's true and prints value as '1', suppose you did (a! =c) which is true and !(a! =c) becomes false and prints as '0' ,hope this helped :)
NOTE: you have to declare the char as char c='5';
https://code.sololearn.com/cxcSNpamZo81/?ref=app

Answer 2

Int a=5,b=6;
Int c=a==b ;
If i will print the. Value of c thn it will give false becoz 5==6 its false but if i write( not) operator ! Then it will give true !(5==6) now here bracket will solve first so 5==6 false then not operator work opposite for ture not operator give false so it will be true .
But in your case u define 6 as a int but 5 as a char you can not compare int variable to char variable so here this will be false then ! Will change true value to false value to true so Output will be 1.
If you will run this example it will give 0 as a Outputs becoz u can compare similar type of data .

int a=6;
char c= 5;
printf("%d",(a==c));

Ig i write
Float a=0.1
if(a==0.1)

This will give false find reason .

Answer 3

It is too easy to understand, listen! The NOT operator is return true for false condition, and return false for true condition, here , int a = 6; char c = 5;
Always they are false, so compiler gives you 1 for false condition.. I hope you understood! :)