i was trying to solve security code for the code coach but it gives me error in (if i > 0 and i <= length-1:)

Question

but it gives me error in (if i > 0 and i <= length-1:) if floor TxGx$

floor_map = input("Enter the floor map ")
floor_map = [floor_map.replace("x", "")]
#print(floor_map)
length = len(floor_map[0])
i = 0
p = ""
while i in range(length):
a = floor_map[0][i]
if a == "$" :
if i > 0 and i <= length-1:
if floor_map[0][i-1] == "T" or floor_map[0][i+1] == "T" :
p = "ALARM"
i = length
else:
p = ""
elif i == 0 :
if floor_map[0][i+1] == "T" :
p = "ALARM"
i = length
else:
p = ""

elif i == length :
if floor_map[0][i-1] == "T" :
p = "ALARM"
i = length
else:
p = ""

i += 1
if p != "ALARM":
p = "nothing"
print(p)

Ajith

Answer 1

the code right below it. [i+1] could lead into index out of bound error.
since i<=length-1.
[i+1] can get equal to length.
but since list is start with 0. the last index must me at length-1. so if i+1 is equal to length, its out of bounds

Answer 2

Md. Nasif-ur-Rahman Rimon sir I was just testing the code by adding some extra print but I would be greatful if you could just explain me why is it giving me error in the 11 statement i.e. if i > 0 and i <= length-1:

I didn't wanted the solution for this problem

Answer 3

‎يوسف سعد‎ sir it is python not java

Answer 4

Thanks

Answer 5

This is not the correct way to do the problem! You have to find a better shorter way to do it!
According to PEP8 => there's only 1 best method to do a problem!
Why to complicate things?
for eg:

x = input().replace("x","")
if "$T" in x or "T$" in x:
print("ALARM")
else:
print("quiet")

Answer 6

and is not an operator in java
if you want to check that two conditions are true use '&&'.

Answer 7

Sorr my bad

Answer 8

Wrong way 😅