Any one tell me pre-increment of array???How the value of x became 10???

Question

*🎙️Predict the output of the following code segment:*

int main()
{
int array[10] = {3, 0, 8, 1, 12, 8, 9, 2, 13, 10};
int x, y, z;
x = ++array[2];
y = array[2]++;
z = array[x++];
printf("%d %d %d", x, y, z);

return 0;
}

🎯a. 10 9 10

Answer 1

x increases at array[x++]. Before that, x is initialized with ++array[2] which is 9.

Answer 2

Array index start from zero here array[2] index value is 8 and
In expression
x=++array[2] =++8 ; here 8 will increase by 1 so 9 will assign to x
x=9
After that y=array[2] assigned to y and which value 9 becoz in x value of 2nd index is incresed
After next line
z=array[x++]; x was 9 so
z=array[9] which value is 10
So z =10 and
z=array[x++] here you used Post increment after assign value 10 it will increase becoz post inc increment after calculate expression so present value of x will be 10 and c is procedural language so now x is changed so we will use present value of x

So final Output is
x=10
y=9
z=10

Answer 3

Thanks