question about a C constant definition

Question

#define square(x)(x*x)
int main(){
int x,y=1;
x=square(y+1);
printf("%d",x);
return 0;
}

in this code isnt the printed value suppoesed to be 4? The answer states it is 3.

Answer 1

No.

squire(y+1) is replaced by its definition of macro as
(y+1*y+1) and y =1 then
=>(1 +1*1+1)
= (1+1+1)
= 3.

Macro definition just replaced as it is before evaluating...