Can we use a user input to define what's it's category in an array ?

Question

All I want is the user to type in a number ( a temperature in Celcius) like the code under, and the output would be a word from the array sorted out by few "if else". I'm begining and just trying to learn.

import java.util.Scanner;

class Program {
public static void main(String[] args) {
String[ ] myTemps = {"Cold", "Mild", "Warm", "Hot"};
int x = 0;
Scanner thermometer = new Scanner(System.in);
System.out.println("What is the temperature in celcius?");
int temperature = thermometer.nextLine();
//x = temperature;
if(temperature > 0) {
if(temperature > 15) {
if(temperature > 30) {
System.out.println(myTemps[3]);}
else {
System.out.println(myTemps[2]);}
}else{
System.out.println(myTemps[1]);}
}else{
System.out.println(myTemps[0]);
}
}
}

Answer 1

int temperature = Integer.parseInt(thermometer.nextLine());

Or you can just use

int temperature = thermometer.nextInt();

assuming you want to parse the int

Answer 2

O, ye, when you use .nextLine() it reads it as a string, so to assign it to an int value you'd have to convert it with Integer.parseInt(string); or you can read it as an int with (scannerObj).nextInt();

Answer 3

Odyel,

Not sure what it would do with the parse... but I tried both and it still does the same error.

Here if you want to see the code link:

https://code.sololearn.com/c5u09tnXQCit/?ref=app
https://code.sololearn.com/c5u09tnXQCit/?ref=app

Answer 4

Works fine for me, what are you inputing? I just entered "75"

Answer 5

Oh.. wait, sorry, my fault, it works perfectly, thanks! Glad to know that only 1 line was wrong

Answer 6

Thanks, it's clear now!