FizzBuzz problem is a well known programming assignment, asked during interviews.

Question

FizzBuzz is a well known programming assignment, asked during interviews.

The given code solves the FizzBuzz problem and uses the words "Solo" and "Learn" instead of "Fizz" and "Buzz".
It takes an input n and outputs the numbers from 1 to n.
For each multiple of 3, print "Solo" instead of the number.
For each multiple of 5, prints "Learn" instead of the number.
For numbers which are multiples of both 3 and 5, output "SoloLearn".

You need to change the code to skip the even numbers, so that the logic only applies to odd numbers in the range.

n = int(input())

for x in range(1, n):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

Help me to solve this problem

Answer 1

#Here's the code:

n = int(input())

for x in range(1, n,2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
continue
elif x % 3 == 0:
print("Solo")
continue
elif x % 5 == 0:
print("Learn")
continue
else:
print(x)

Answer 2

Solution
n = int(input())

for x in range(1, n,2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

Answer 3

The range begins with 1, to ensure that only odd numbers are processed, you can use the range stepping of 2

for x in range(1, n, 2):
# codes here

And cache the modulo results so your code doesn't have to do it multiple times.

Answer 4

Solution would be
n = int(input())

for x in range(1, n):
if x %2 !=0:

if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)
else:
continue

Answer 5

Solution
Rmbr to add the 3rd argument in the range to give it a sequence
in this case our third argument will be 2

n = int(input())

for x in range(1, n,2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
continue
elif x % 3 == 0:
print("Solo")
continue
elif x % 5 == 0:
print("Learn")
continue
else:
print(x)

Answer 6

Use this code ....proof
n = int(input())

for x in range(1, n,2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

Answer 7

n = int(input())

for x in range(1, n,2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
continue
elif x % 3 == 0:
print("Solo")
continue
elif x % 5 == 0:
print("Learn")
continue
else:
print(x)

Answer 8

n = int(input())

for x in range(1, n,2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
continue
elif x % 3 == 0:
print("Solo")
continue
elif x % 5 == 0:
print("Learn")
continue
else:
print(x)
#if you like this program upvote me

Answer 9

n = int(input())

for x in range(1, n):
if x % 2 == 0:
continue
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

Answer 10

You just have to write a line of code to skip the even numbers, but that line must come first in the code block, because there are even numbers that are multiple of 3 an 2 at the same time (ex: 6), and even numbers that are multiple of 3 and 5 (ex: 60):

n = int(input())
for x in range(1, n):

if x % 2 == 0: #to skip the even numbers
continue

elif x % 3 == 0 and x % 5 == 0:
print("SoloLearn")

elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

Answer 11

n = int(input())

for x in range(1, n,2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

Answer 12

Try this
x = int(input())

for i in range(1, x,2):
if i % 3 == 0 and i % 5 == 0:
print("SoloLearn")
elif i% 3 == 0:
print("Solo")
elif i % 5 == 0:
print("Learn")
else:
print(i)

Answer 13

This is mine.

n = int(input())

for x in range(1, n, 2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
elif x % 2 > 0:
print(x)
continue

Answer 14

# it is answer from Aman Saini , I hope this answer is useful for you
n = int(input())

for x in range(1, n,2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")

elif x % 3 == 0:
print("Solo")

elif x % 5 == 0:
print("Learn")

else:
print(x)

Answer 15

#Solution would be
n = int(input())

for x in range(1, n):
if not x %2==0:
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

Answer 16

n = int(input())

for x in range(1, n):
if not x % 2 == 0:
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

Answer 17

n = int(input())

for x in range(1, n,2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
continue
elif x % 3 == 0:
print("Solo")
continue
elif x % 5 == 0:
print("Learn")
continue
else:
print(x)

just add continue

Answer 18

n = int(input())
for i in range(n):
if i%2==0:
i+=1
elif i%3==0 and i%5==0:
print("SoloLearn")
continue
elif i%5==0:
print("Learn")
continue
elif i%3==0:
print("Solo")
continue
else:
print(i)

Answer 19

Check this out;

n = int(input())

for x in range(1, n):
if x % 2 == 0:
continue
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

Answer 20

n = int(input())

for x in range(1, n, 2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
continue
elif x % 3 == 0:
print("Solo")
continue
elif x % 5 == 0:
print("Learn")
continue

elif x%2 == 0:
break

else:
print(x)