Why I can't get the total of the odd nunber?

Question

https://code.sololearn.com/c312m1EaD2UI/?ref=app

Why the result always zero??

Answer 1

It is ok to use the while loop, but it is much easier to do this task with a for loop. With a for loop, you dont't have to care about the length of the iterable and you don't need to use a counter variable.

items = [23, 555, 666, 123, 128, 4242, 990]
sum_ = 0
for num in items:
if num % 2 != 0:
sum_ += num
print(sum_)

# or with a comprehension:
print(sum([i for i in items if i % 2 != 0]))

Answer 2

Joe Ma

items = [23, 555, 666, 123, 128, 4242, 990]

sum = 0
n = 0
while n < len(items):
num = items[n]
n+=1
if num % 2 == 0:
continue
else:
sum += num

print(sum)

Answer 3

Show this code
https://code.sololearn.com/cs2U4f52tYBK/?ref=app

Answer 4

sum = 0
n = 0

while n < len(items):
num = items[n]
if num % 2 != 0:
sum += num
n+=1
print(sum)

Answer 5

Your num doesn't change at all. It remains to be the items[0] for the whole loop.

Answer 6

And move the else statement to the left of the code then it is called.