+ 1
¿Que significa?//What does it mean?
¿Que significa la salida de este código java?//What does the output of this Java code mean? . https://code.sololearn.com/cyJKyEqGVO16/?ref=app . Y porque funciona la salida de este otro código en C.//And why does the output of this other code in C? . https://code.sololearn.com/c3C27Apy81ha/?ref=app
25 Antworten
+ 5
Whats significant in spanish.
+ 4
Just for fun.
+ 1
Thank you and good evening I was also thinking of turning everything off
0
Did you know about Oriented Object?
public class Person
{
String name;
int age;
Person(String na) //constructor
{
this.name = na;
}
}
Person people = new Person("Daniel");
So, new Person() is a object and "people" is a reference, it is the address on memory.
String is a object, and variable of String are reference (memory address).
Var args is a list of parameter, before you start your program you can set a list... Like the constructor.
When calling if to scren, have method called toString(); and it try change addres memory into info. (You can re-write toString(); so it would show something different).
0
About C, I'm NOT SURE, but sometimes some address have resudie.
Think variable are cup, so when you declare a variable are you taking a cup, and put value is like put tea, cofee, water...
But if you not take care you can take a dirty cup, so it would have something on...
Or it or default value, so it show "2", but I think is because some "dirty address", getting a address already on use.
0
Java: thank you very much?.
Is there a way to access the objects in the class without knowing their names?
0
Sorry, I didn't understand, can you give me a example?
0
ok.
0
Thank you very much. I want to know how the function System.out.println (); Pull the text across the screen.
0
https://docs.oracle.com/javase/9/docs/api/java/lang/System.html
"System" is class.
Inside have "out" that is a reference.
Calling "println()" method.
0
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I get this erro a long time ago.
0
For classes, it call toString(), it is a method from all Object.
Class Person()
{
String name;
int age;
Person(String nam)
{
this.name = nam
}
}
public Program
{
public static void main(String[]args)
{
Person people = new Person("Daniel");
System.out.println(people);
//Will put some weird memory address, it is calling toString()
System.out.println(people.toString()); // we dont need put toString() because println is calling it already. But we can, same thing.
}
}
But if add
public Person
{
@Override
public toString()
{
Return "My person is " + this.name;
}
}
When:
System.out.println(person.toString());
Output: My person is Daniel
And if:
System.out.println(person);
Output: My person is Daniel
So, use or not, but the "code memory address" is a method that previous programming did.
0
Thank you very much 😁. Now I'm going to see if I understand. Because in Java I am the basic level.
0
No worry, when you get Oriented Object you will understand better, just go on your rythym and lvl.
0
Can I make another question different? But in C.
0
Ok can ask.
0
I have put this post to ask: the new driver's license, but it does not come out because it works for me.
.
.
question:
https://www.sololearn.com/coach/18?ref=app
.
.
Answer:
https://code.sololearn.com/cP7FGJ3R4jC8/?ref=app
0
What is the ask?
Obs: remember even if you're fisrt the question say how much till you go off. So you need wait your time while processing.
0
I do not understand
0
Turning pc on, analysing...