Can you solve this?

Question

Return the sum of the numbers in the array, returning 0 for an empty array. Except the number 13 is very unlucky, so it does not count and numbers that come immediately after a 13 also do not count.

sum13([1, 2, 2, 1]) → 6
sum13([1, 1]) → 2
sum13([1, 2, 2, 1, 13]) → 6

Answer 1

Here is a solution in Python that implements the given requirements:

def sum13(nums):
sum = 0
skip = False
for i in range(len(nums)):
if nums[i] == 13:
skip = True
elif not skip:
sum += nums[i]
else:
skip = False
return sum
This solution uses a loop to iterate through the nums array. If the current number is 13, a flag skip is set to True to indicate that the next number should be skipped. If skip is False, the current number is added to the sum. After processing each number, skip is reset to False. The function returns the sum as the result.