Shorthand operator is giving different result

Question

i=i-j and i-=j both are giving different results. Why this is happening?

Answer 1

R_N
Can you describe the purpose and goal of the code, briefly? and which line(s) were troubling you?

I was actually expecting a saved code link, so we can refer to line numbers easily. Raw text code doesn't have line numbers obviously.

(Edit)
Some examples for input may also help ...

Answer 2

For the sake of clarity, please share the code's link 👍

Answer 3

It result same.
May you have doing something wrongly.. Chech again..

Answer 4

https://code.sololearn.com/cb644x1w1r03/?ref=app

It's not possible. both will give same.

NOTE - suppose a variable hold a number 5 if you do like this

int num = 10;
num -= 3; //Now the value of num changed
System.out.println(num);// now num is 7
num = num - 3; //Now num is 7 not 10 and after it the num changes
System.out.println(num);

OUTPUT WILL BE -
7
4

These are different maybe this is your mistake .

Answer 5

R_N
In the 2nd expressions of instruction
I = i -el-1 ; it's short form is i -= (el+1)
You may using i -= (el-1).

Answer 6

https://code.sololearn.com/c9B93tg72BPi/?ref=app

Answer 7

R_N No. Am getting same output..
Add what input you are giving and what you getting as output?

Answer 8

Jayakrishna🇮🇳
Check for the input
1
2 3
2 5 7 9 11 13
Using shorthand operator the answer is 33
And normal assignment (i = i-el) is giving 20

Answer 9

Jayakrishna🇮🇳
Thanks! You are right. Got the answer.

Answer 10

I have a problem that i can't solve alone anyone to help

Answer 11

shortHand just & just is meant to compile cods faster.

Answer 12

Hi Can i talk to you

Answer 13

sure