How to selection number in integer

Question

i have an array of integer but i have to random that number with method random

but the problem is the number digit is 10 but i wont to random just 6 digit from array of integer

like this
if you had a number : 1937261838
random 6 digit : 178389

how to selection that digit/remove that number

Answer 1

Assuming I read the question right: (Not 100% sure what you mean)

If you want to create your own methods instead of using an already existing one you can do something like this: (this may not be exactly what you want to use, however just do what @Meharban said if you are a beginner.)

*Create a method to find the Index of the number you want to delete; example here:
int indexOf(int num, int[] arrayToFind){
// this is just linear search (im being lazy)
for(int i = 0; i < arrayToFind.length; i++)
if(num == arrayToFind[i])
return i;

return null; // nothing was found
}
Now you can use that index to remove it by creating a new list; example:

int[] afterRemoval(int index, int[] listToUse){

int[] newArray = new int[listToUse.length-1];
int curI = 0; // the index to add to newArray
/* make sure indexOf finds something before using this function[because of how I created the size of the newArray */
for(int i = 0; i < listToUse.length; i++){
if(i != index){
newArray[curI] = listToUse[i];
curI++;
}
}
return newArray;
}
I'm basically just locating the number we want to remove, then making a new array that does not include that number.

Answer 2

There are quite a few methods for that. You can convert it to list and then remove it.

Answer 3

how to remove it ?

Answer 4

list.remove();