Why is the output 6 of this code?

Question

#include <iostream>
using namespace std;

int main() {

int i,x;
i = 0;
x = 1;
for(int x=1; x<4; x++)
i++;
x++;
i*=x;
cout << i;
return 0;
}

Answer 1

In the for loop, i gets incremented three times, and i stores the value of 3. Variable x gets incremented once, to become 2. We then multiply i with x and store the result in i. We print the value of i, which is 2*3, hence getting 6.