How to make it appear every multiple of 5 "beep"

Question

#include <iostream>
using namespace std;

int main() {
int n;
cin >> n;
for(int x=n; x>0; x--)
{
cout<<x<<endl;
if(x %5 == 0){
cout<<"beep"<<endl;
}
}

}

Answer 1

Lidandi Biki
The problem is, the "cout << n << endl;" is placed before the condition "if (x % 5 == 0)", hence, the number with the multiple of 5 will print first, before the word "beep"

Solution:
Place the "cout << x << endl;" to an else statement so that if a number is multiple of 5, it will print the "beep" without the number.

https://code.sololearn.com/cJI74MyH5o0X/?ref=app

Answer 2

nicko's code is doesn't work, look for my code

#include <iostream>
using namespace std;

int main() {
int n;
cin >> n;

for (int i=n;i>0;i--)
{
cout << i;
if(i % 5 == 0)
cout << "Beep";
}

return 0;
}

Answer 3

Иван Чикyнов Sorry, but I dont think thats the right code, it is just the same with the previous one, you just removed the "endl".

Answer 4

ok

Answer 5

Thanks everyone, this code is work