+ 1

Hii everyone, please tell me can I make this code more optimise? If yes, then also tell how.

https://code.sololearn.com/cXyY2XcpgczB/?ref=app

15th Dec 2020, 12:04 PM
Nilesh Diwakar
Nilesh Diwakar - avatar
2 Antworten
+ 1
Thanks bro, I will
18th Dec 2020, 12:34 PM
Nilesh Diwakar
Nilesh Diwakar - avatar
0
You can reduce one loop. The loop for making all elements of answer matrix as 0 can be eliminated . Instead it can included in the multiplication loop itself. #include <iostream> using namespace std; int main() { int n1,n2,n3; cin>>n1>>n2>>n3; int m1[n1][n2]; int m2[n2][n3]; for(int i=0;i<n1;i++){ for(int j=0; j<n2;j++){ cin>>m1[i][j]; } } for(int i=0;i<n2;i++){ for(int j=0; j<n3;j++){ cin>>m2[i][j]; } } int ans[n1][n3]; for(int i=0;i<n1;i++){ for(int j=0; j<n3;j++){ ans[i][j] = 0 ; for(int k=0; k<n2; k++){ ans[i][j] +=m1[i][k]*m2[k][j]; } } } for(int i=0;i<n1;i++){ for(int j=0; j<n3;j++){ cout<<ans[i][j]<<" "; } cout<<endl; } return 0; } You can also use function for getting input and printing output it may also reduce another loop.
16th Dec 2020, 11:07 AM
DAMODHARAN. R
DAMODHARAN. R - avatar