Write a program to take input from user and check whether greater than zero , Less than zero , and Zero . Using try catch throw

Question

#include<iostream>
using namespace std;
int test(int x){
try{
int y , int z;
if (x>0)
throw x ;
else if (x<0)
throw y ;
else
throw z ;

}
catch (int x){
cout<<" Less than zero ";
}
catch (int y)
{
cout<<"Greater than zero ";

}
catch (int z)
{
cout<<" Zero ";
}
return 0;
}

int main ()
{
int a ;
cout<<"Enter any number "<<endl;
cin>>a;
test(a);
return 0;

}

Answer 1

Well, you can throw certain value, catch and return it to the caller. This is ridiculous though 😁

#include<iostream>

int test( int x )
{
try
{
if ( x > 0 )
throw 1;
else if ( x < 0 )
throw -1;
else
throw 0;
}
catch ( int ex )
{
return ex;
}
}

int main ()
{
int a;
const char* status[ 3 ] { "Less than zero", "Zero", "Greater than zero" };

std::cin >> a;
std::cout << status[ test( a ) + 1 ];
return 0;
}

Answer 2

Hello problem is solved

Can you explain

Why you use
const char* status[ 3 ] { "Less than zero", "Zero", "Greater than zero" };

Answer 3

It's an array, and we get the desired element index by adding 1 to the return value of function `test`.

When `test` returns
-1 => -1 + 1 = 0
index 0 -> "Less than zero"

0 => 0 + 1 = 1
index 1 -> "Zero"

1 => 1 + 1 = 2
index 2 -> "Greater than zero"

Answer 4

You do know that you can achieve this by using conditionals right?

Answer 5

Ipang I know but I need to complete using try catch & throw