A problem using while loop

Question

Hey guys I try to resolve this problem

Requirements: A natural number N is entered from the keyboard.The first N numbers that are odd are displayed in ascending order
Restrictions and specifications :
0<N<1000000
Exemples:
Input data:
5,3
Output data
1 3 5 7 9
1 3 5

Answer 1

Benjamin Jürgens your code is really simple, good and exactly as you described above.

Answer 2

> Ok and how to do that?
Take the code you have written and change it according to what i wrote. I think my description is already a detailed instruction and straight forward to follow

Answer 3

What Problem you have in this code it is working and printing values

Answer 4

The idea is my input is 5 so I should have 5 numbers and my program show just 3

Answer 5

A hint for you Andrei Macovei :
as I undestood your imput are two integers separated with comma not one number.
So have to receive two numbers. How, try to find out it.

Answer 6

Not really it s for beginners this problem and it s request just a while loop

Answer 7

I give an example
Input :3
Output:1 3 5

Answer 8

It says print first N odd numbers, not odd numbers up to N.
So either
let nr count 1 2 3 ... N and figure out the mathematical operations to apply to each nr to get output 1 3 5 ...
or
start at 1, increase in steps of 2 and figure out when you have to stop

Answer 9

Syrah Algena no array is needed here

Answer 10

If you like this will help you Andrei Macovei :

https://code.sololearn.com/cTcHQ83uJhZt/?ref=app

Answer 11

You can also use a for loop starting at 1 and a step of 2.

Answer 12

Andrei Macovei for this problm u need to use array u can easily do it first define a number how much u want to enter then take user input how many values u want to print

Answer 13

JaScript as I understood, example is really 2 examples:
input => output
5 => 1 3 5 7 9
3 => 1 3 5

Answer 14

Benjamin Jürgens its depend on your approach i thought array is much better

Answer 15

I tried that :
#include <iostream>
using namespace std;
int main(){
int n,nr;
cin>>n;
while(nr<=n){
nr++;
if(nr%2==1)
cout<<nr;
}
return 0;}

Answer 16

Yes exactly but I don't know how to implement

Answer 17

Here i have used predefined element if u want u can take from user use cin with for loop

#include <iostream>
using namespace std;
int main(){
int n,i=0;
int array[]={1, 2, 3, 4, 5, 6 ,7 ,9 ,11, 13};

cout<<"how many numbers u want to print\n";
cin>>n;
while(i<n){

if(array[i]%2==1)
{
cout<<array[i]<<" ";

}
i++;
}
return 0;
}

Answer 18

Syrah Algena
0<N<1,000,000
Do you really want to write that array down?
And if you fill it in a loop, then output in another loop, you can instead just output directly

Answer 19

Andrei Macovei you don't have to change much, just follow one of my suggestions.
I'd prefer the first. Delete the if statement and instead output in every iteration, but not nr but the odd number calculated from nr
1=>1, 2=>3, 3=>5, 4=>7, 5=>9, ... 100=>199
It's just basic math

Answer 20

Ok and how to do that?