Can anyone tell me what's wrong in this

Question

Entrance to the club is only permitted in pairs.
Take the number of customers in the club as input, and, if all of them have a pair, output to the console "Right", otherwise output "Wrong".

Sample Input
14

Sample Output
Right

//mycode
function main(){
var numberGuests = parselnt(redLine(), 10)
if (numberGuests%2===0){
alert ("Right")
}
else{
alert("Wrong")
}

Answer 1

Simba
'===' is fine as soon as both operand are of same type (wich is the case here)...

Answer 2

NIKHIL SONAWANE
you need to properly close curly brace of your main function ^^

Ollie Q
';' is not compulsary in javascript (even if it's better practice to put them)

Answer 3

Ollie Q Semicolons are not mandatory in JavaScript with linebreaks.
NIKHIL SONAWANE You’re missing another } at the end.

Answer 4

you still doesn't close your function curly braces, and you introduce syntax error in 'if' condition ^^

Answer 5

NIKHIL SONAWANE Go to your original code you put in the question. Add another curly brace } to the end. It should work.

Answer 6

function main() {
var numberGuests = parseInt(readLine(), 10)
// Your code here
if ((numberGuests%2)==0) {
console.log('Right')
} else
{
console.log('Wrong') } }

Good Luck

Answer 7

function main() {
var numberGuests = parseInt(readLine(), 10)
// Your code here
var numberGuests = 2;
if(numberGuests 14 % 2 == 0){
console.log("Right");
}
else if(numberGuests ! = 2){
console.log("Wrong");
}
Still not working 😭😭

Answer 8

You are missing a curly brace } at the end of the code

Answer 9

missing “;” on end of first line and on both alert()s

Answer 10

Missing a curly brace }

Answer 11

Change === to == because they aren't same

Answer 12

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