Working with files filling up with numbers

Question

WoNT WORK

DESCRIPTION:

Take a number N as input and write the numbers 1 to N to the file "numbers.txt", each number on a separate line.

Sample Input:
4

Sample Output:
1
2
3
4

The given code reads the content of the file and outputs it.

Answer 1

n = int(input())

file = open("numbers.txt", "w+")
#your code goes here

for line in range(1, n+1):
file.write(str(line)+"\n")

file.close()

f = open("numbers.txt", "r")
print(f.read())
f.close()

This is also works ....

Answer 2

This is my answer.

n = int(input())
i = 1
file = open("numbers.txt", "w+")
#your code goes here
while i <= n:

file.write(str(i) + "\n")
i += 1

file.close()

f = open("numbers.txt", "r")
print(f.read())
f.close()

Answer 3

n = int(input())

file = open("numbers.txt", "w+")
#your code goes here

for line in range(1, n+1):
file.write(str(line)+"\n")

file.close()

f = open("numbers.txt", "r")
print(f.read())
f.close()

Answer 4

n = int(input())

file = open("numbers.txt", "w+")
#my code is here
for i in range(n):
file.write(str(i+1)+"\n")
print("\n")
file.close()

f = open("numbers.txt", "r")
print(f.read())
f.close()

Answer 5

with open("numbers.txt", "w") as file:
for i in range(1, 10000001):
file.write(f"{i}\n")

Answer 6

not sure how to complete it

n = int(input())

file = open("numbers.txt", "w+")
#your code goes here

f = open("numbers.txt", "r")
print(f.read())
f.close()