Hash256, password

Question

Hi.I have a task to access some password which its algorithm is given in a csv file with name.
Such as this:
Daniel,99b057c8e3461b97f8d......
And i have to put the code in a fuction and only use these 2 libraries:
Csv and sha256
And because the code is being checked by a system and gives me a grade, i can't change the main structure.please check if i got it
import csv
from hashlib import sha256
def hash_password_hack(input_file_name, output_file_name):
hash_password_to_password = {}
with open(input_file_name, newline='') as f:
psswords_singer = csv.reader(h)
with open(output_file_name, 'w', newline='') as f:
writer = csv.writer(w, delimiter=',')
for password in range(1000,10000):
hashing_number = sha256(b'%i'% password).hexdigest()
hash_password_to_password[hashing_number] = password
for row in psswords_singer:
name_users = row[0]
for key in row[1:] :
writer.writerow([name_users,hash_password_to_password[key]])

Answer 1

The system itself gives the file to the code as an example. I solved it without the function and by giving the file address. But we have to use a function so that the checking system can use it to check different files

Answer 2

how should we check it without csv sample?

Answer 3

at least in which colon the hash is located?