Why does the catch block execute first?

Question

// A Class that represents use-defined expception
class MyException extends Exception
{
public MyException(String s)
{
// Call constructor of parent Exception
super(s);
}
}

// A Class that uses above MyException
public class Main
{
// Driver Program
public static void main(String args[])
{
try
{
// Throw an object of user defined exception
throw new MyException("GeeksGeeks");
}
catch (MyException ex)
{
System.out.println("Caught");

// Print the message from MyException object
System.out.println(ex.getMessage());
}
}
}

Answer 1

What do you mean?
The "try" block is executed first in the "main" function and it throws your custom exception (MyException).
Then the "catch" block is executed, because it is configured to catch your custom exception