The code incorrectly calculates the sum of the digits of the number. For example, if you enter 157, then the output will be LOCK

Question

https://code.sololearn.com/c9JM7vSLRwvt/?ref=app

Answer 1

The problem is actually your second term bracket. You shouldn't and two numbers, because it will return True/False
(1 and 1) == True # True is also 1
so instead you can just remove the bracket and the and

c // 100 + c // 10 + c % 10 == 13:

however, the second term will be wrong, so you need to adjust it a bit

c // 100 + c // 10 % 10 + c % 10 == 13:

so let's say 157,
157 //10 = 15
15 % 10 = 5, which is the number you want

Another alternative and maybe easier way is to loop the string and plus the int of each character

c = input() # didn't convert to int here
total = 0
for char in c:
total += int(c)

And here is the standard way everyone getting the sum of tbe digits

c = int(input())
total = 0
while c > 0:
total += c % 10
c //= 10

Answer 2

Polina Voqy

What do you expect and what are you doing here?

https://code.sololearn.com/cw6Cz4ogRgPk/?ref=app

Answer 3

Thanks for the help

Answer 4

It is lock. When you input number less than 100 and more than 999 then you'll got FALSE. If sum of digits of a number is 13 output is ENTER. In other occasions LOCK.
But when I write 157 or 247 and also some more, it outputs LOCK

Answer 5

Thanks for the explanation

Answer 6

Я из России