Why I am getting empty list with this code. Can anyone explain?

Question

This is a code from list comprehension in python

car = ["Maruti","Swift","Ford","Bugati"]
newlist = [x for x in car if x != "Maruti" in x ]

print(newlist)

# this is the simple code please explain

Answer 1

Aman Kumar the list comprehension is just equivalent to :
newlist=[ ]
for x in car:
if x!="Maruti":
newlist.append(x)

Hope you got it .

Answer 2

Calvin Thomas is correct. You essentially have a chained 'and' logical statement. If you remove the 'in x' from the end of the list comprehension, you will result in a list with all the elements minus "Maruti". The reason it is otherwise empty is because the only condition in which "Maruti" in x is True is the first where x is "Maruti", and for that element x != "Maruti" is False so for every evaluation of the conditional, the result is likewise, False.

Answer 3

In my opinion, the logic simplifies to 'x != "Maruti" and "Maruti" in x', which is False considering the data here. I guess that this needs some clarification, though.

Answer 4

In order to get desired results the list comprehension should be :

newlist=[x for x in car if x!="Maruti" ]

Remember we can find x in car only then it'll be true and if you wanna find x in x then it'll return false .

Answer 5

As a beginner i am still confused🤔🤔🤔🤔🤔🤔🤔🤔

Answer 6

Aman Kumar
it's simply finding all the values from the list car whose value not equal to "Maruti" and making an another list named newlist of all those values .
That is
print (newlist) would give

["Swift","Ford","Bugati"]

Hope you understand

Answer 7

Can anyone explain
I got confused in lists comprehension.